## Aptitude question and answer on Problems on age

1 | Santosh is four times as old as his son. four years later the sum of their ages will be 43 years. The present age of son is A. 5 years B. 7 years C. 8 years D. 10 years Answer : B. 7 years Explanation: Let son's age = x then, Santosh's age =4x \(\dot{..}\) (x+4)+(4x+4)=43 x=7 \(\dot{..}\)Present age of the son = 7 years. |

2 | Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present ages? A. 30 B. 35 C. 40 D. 45 Answer : B. 35 Explanation: Let the present age of P and Q be 3x and 4x respectively. Ten years ago, P was half of Q's age => (3x – 10) = \(1\over2\)(4x – 10) => 6x – 20 = 4x – 10 => 2x = 10 => x = 5 total of their present ages = 3x + 4x = 7x = 7 × 5 = 35 |

3 | A man's age is 125% of what it was 10 years ago, but \(83\dfrac{1}{3}\%\) of what it will be after 10 years. What is his present age? A. 40 B. 50 C. 60 D. 70 Answer : B. 50 Explanation: Let the age before 10 years = x Then \(125x \over100\) = x + 10 =>125x = 100x + 1000 => x = \(1000 \over 25\) = 40 Present age = x + 10 = 40 +10 = 50 |

4 | Present ages of Kiran and Syam are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Syam's present age in years ? A. 24 B. 25 C. 26 D. 27 Answer : A. 24 Explanation: Ratio of the present age of Kiran and Syam = 5 : 4 Let the present age of Kiran = 5x Present age of Syam = 4x After 3 years, ratio of their ages = 11:9 => (5x + 3) : (4x + 3) = 11 : 9 => 9(5x + 3) = 11(4x + 3) => 45x + 27 = 44x + 33 => x = 33-27 =6 Syam's present age = 4x = 4×6 = 24 |

5 | Five years ago, the total of the ages of a father and his son was 40 years. The ratio of their present ages is 4 : 1. What is the present age of the father ? A. 30 years B. 20 years C. 25 years D. None of these Answer : D. None of these Explanation: Let son's age = x. Then father's age = 4x \((x-5)+(4x-5)=40\) \(⇒x = 10\) Present age of father = 40 years |

6 | One year ago Jaya was four times as old as her daughter Nikitha. Six years hence, Mrs.Jaya's age will exceed her daughter's age by 9 years. The ratio of the present ages of Jaya and her daughter is : A. 9 : 2 B. 11: 3 C. 12: 5 D. 13: 4 Answer : D. 13: 4 Explanation: Let Nikitha's age 1 year ago = x Then Jaya's age 1 year ago = 4x After 6 years their ages are \(4x+7, x+7\) \((4x+7) - (x+7) = 9 \) or \(x = 3\) Present age of Jaya = (12+1) years = 13 years Present age of Nikitha = (3+1) years = 4 years Ratio of their ages = 13 : 4 |

7 | The sum of the ages of a mother and daughter is 50 years. Also, 5 years ago, the mother's age was 7 times the age of the daughter. The present ages of the mother and daughter respectively are : A. 35 years, 15 years B. 38 years, 12 years C. 40 years, 10 years D. 42 years, 8 years Answer : C. 40 years, 10 years Explanation: Let the daughter's present age be x years. Then, mother's present age = (50-x) years. Now, \(7(x-5)=(50-x-5)\) or \(x = 10\) So, their present ages are 40 years and 10 years. |

8 | The sum of the ages of a son and father is 56 years. After 4 years, the age of the father will be three times that of the son. Their ages respectively are: A. 12 years, 44 years B. 16 years, 42 years C. 16 years, 48 years D. 18 years, 36 years Answer : A. 12 years, 44 years Explanation: Let the present ages of son and father be x years and \((56-x) \) years respectively. Then \((56-x+4)=3(x+4)\) or 4x =48 or x = 12 So their ages are 12 years, 44 years respectively. |